Web design rates - Methods 123 System.out.println( Multiply int * int ); return x
Methods 123 System.out.println( Multiply int * int ); return x * y; } public double multiply(double x, double y) { System.out.println( Multiply double * double ); return x * y; } public double multiply(int x, double y) { System.out.println( Multiply int * double ); return x * y; } public int multiply(int x) { System.out.println( Multiply int * itself ); return x * x; } public int multiply(int x, int y, int z) { System.out.println( Multiply three ints ); return x * y * z; } } . Method Overloading You can overload a method as long as the parameter lists are distinct enough for the compiler to be able to distinguish which method you want to invoke. Certainly if the number of parameters is different, the overloading is valid, as shown in the following two method signatures: public float computePay(double d, int x); //Two parameters public float computePay(double d); //One parameter If you simply change the name of the parameter, it is not valid. For example, the following two methods could not appear in the same class because this is not valid overloading: public void setDay(int x, int y, long z); public boolean setDay(int a, int b, long c) //No! The preceding two methods have the same name and the same number of parameters, and the parameters appear in the same order. The compiler would not be able to distinguish between the two methods and would generate a compiler error. Note that changing the return value does not affect whether the overloading is valid or not. However, changing the order of parameters is just like changing the parameter list. For example, the following two methods demonstrate valid method overloading: public void setDay(int x, int y, long z ; public boolean setDay(long a, int b, int c);
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